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Required disk space, Gb = N (pcs.) * K (evitems/hr) * T (days) * 24 (hrs/day) * 2.4 (Kb) / 1024² (Kb/Gb)

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K is an average number of events from an items per object per hour. It can be estimated experimentally in operation conditions.

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Example. Let us have 75 objects, each of them processes 1 item in 5 seconds (~3900 events ~720 items per hour). Archive depth is 90 days, 16 hours per day.

Required disk space, Gb = 75 (pcs.) * 3900 720 (evitems/hr) * 90 (days) * 16 (hrs/day) * 2.4 (Kb) / (1024*1024) (Kb/Gb) = 969 177.98 Gb ~ 1ТВ180 Gb