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General requirements

For Axxon One VMS operation, the disk subsystem must should match the following requirements:

  1. The device must have no less IOPS the Axxon One number of input/output operations (IOPS) of the device should not be less than the IOPS of Axxon One VMS.
    The Axxon One VMS  records video footage to the archive volumes in 4MB blocks with a 10 second interval. If the most recent block is not full after 10 seconds, it will be filled up later.
    Similarly, footage is played back in blocks (except for re-indexation, see the utility for archive managementblocks of 4 MB (megabytes) every 10 seconds. However, if the block is not filled in 10 seconds, a smaller fragment of the block will be recorded, which will be added to later.
    Archive playback is also performed in blocks (except when reindexing, see Console utility for working with archives).This is

    Below you can see how you can estimate the IOPS value for the for Axxon One VMS VMS.


    If the average bitrate per camera is less than 3 ~3.6 Mbps

    If the average bitrate per camera exceeds 3 ~3.6 Mbps

    IOPS during archive recording
    Archive recording includes both data input (writingrecording) and output (reading) operations

    IOPS (writingrecording) = 0,.29 * N

    IOPS (reading) = 0,.035 * M

    IOPS (writingrecording) = 0,.065 * M

    IOPS (reading) = 0,.035 * M

    IOPS during archive playback
     Archive playback includes only output (reading) operations

    IOPS (reading) = 0,.035 * R * S

    IOPS during simultaneous recording and playback

    IOPS (writingrecording) = 0,.29 * N

    IOPS (reading) = 0,.035 * M + 0,.035 * R * S

    IOPS (writingrecording) = 0,.065 * M

    IOPS (reading) = 0,.035 * M + 0,.035 * R * S

    where

    • N is the number of camera channels cameras being recorded;
    • M is the cumulative bitrate over of all camera channels cameras being recorded, in Mbps;
    • R is the cumulative bitrate over of all camera channels cameras being played back from the archive at normal speed (1x), in Mbps;
    • S is the playback speed.


  2. If you use RAID storage, please specify the write-back policy for writing recording to cash memory.

Storage requirements

Size of The disk subsystem will be calculated on the basis of frame resolution and compression, rate of video signal frames per second, number of cameras recording events to the hard drives and other recording parameters. capacity of Axxon One Server should be estimated taking into account the resolution, the compression algorithm, the frame rate of the recorded video signal, the number of video cameras from which the recording to disk(s) takes place and other recording parameters. In addition, the size of the system log and metadata databases should be considered.

Minimum requirements

You need at least 10 GB of free disk space

...

on Windows OS and 5 GB on Linux OS to install the Axxon One VMS package in

...

the Server and Client configuration.

...

See the storage calculations below, taking into account

...

the size of the archive, the size of the database and the size of the archive of the system logs.

Size of

...

the archive

...

The capacity of the disk subsystem can be calculated by the formula:

...

Capacity of

...

disk subsystem (MB) = Time of storing

...

archive (days)

...

* Cameras number

...

* Rate of recording (

...

FPS) * 3.51 * Time of guaranteed recording from a camera (h/day)

...

* Average frame size (KB),

where

Time of storing

...

archive is the required time

...

for storing an archive from one camera, days;

Cameras number is the number of cameras from which recording to the archive takes place;

Rate of recording is the frame rate of recording to the archive, frames per second;

3

...

.51 = (60 sec in min

...

* 60 min in hour) / (1024 KB in MB)

...

is the

...

factor used for KB/s

...

in MB/h conversion

...

;

Time of guaranteed recording from a camera is the number of hours of guaranteed recording from one camera

...

per day

...

;

Average frame size is the average size of the camera frame, kilobytes.

Info
titleNote

Average frame size for of 640х480 resolution is:

Video codec

Average frame size

H.264

from 8 KB to 17 KB

MPEG4

from 8 KB to 35 KB

MJPEG

from 23 KB to 60 KB

Average frame size may vary over a wide range depending on the vendor, the model and the settings of the camera and video image complexity.


Info
titleNote

To calculate the frame size one you can use the ratio, that while when increasing the vertical or horizontal resolution two times, the average frame size will be increased four times (this rule is a relative one and can be applied only to some cameras' camera models).

Examples of calculating a size the capacity of the disk subsystem (without size of syslog databasethe capacity of the system log and metadata databases) are presented below.

Recording parameters

Calculating results

4 cameras with 25 fps FPS and 640х480 resolution, guaranteed recording of 24 hours per day during one week

H.264: from 500 GB to 1 TB
MPEG4: from 500 GB to 2 TB
MJPEG: from 1.3 TB to 3.5 TB

16 cameras with 12 fps FPS and 640х480 resolution, guaranteed recording of 12 hours per day during one week

H.264: from 500 GB to 1 TB
MPEG4: from 500 GB to 2 TB
MJPEG: from 1.3 TB to 3.5 TB

4 cameras with 25 fps FPS and 1280х960 resolution, guaranteed recording of 24 hours per day during one week

H.264: from 2 TB to 4 TB
MPEG4: from 2 TB to 8 TB
MJPEG: from 5.3 TB to 14 TB

...

System log database

The capacity of the system log

...

database should be taken into account when the

...

capacity of the disk subsystem is calculated.

...

The estimated capacity of the system log database is calculated by the formulas:

...

Capacity of

...

system log

...

database (low detection tools activity) = D * T * (0.04 GB / day);

...

Capacity of

...

system log

...

database (average detection tools activity) = D * T * (0.12 GB / day);

...

Capacity of

...

system log

...

database (high detection tools activity) = D * T * (0.48 GB / day);

where 

D is the total number of

...

detection tools created in the system,

T

...

 is the estimated duration of

...

system log storage, days.

Metadata database 

The following formulas can

...

be used to determine the required disk size for the metadata database:

Size of metadata database =

...

 N * T * (0

...

.5GB / day) – sufficient disk size;

Size of metadata database =

...

N

...

* T

...

* (1GB / day) – sufficient disk size plus reserve space;

Size of metadata database =

...

N

...

* T

...

* (5GB / day) – sufficient disk size plus a large reserve

...

,

where

N

...

 is the number of

...

detection tools in the system actively recording metadata

...

. One video camera can have several detection tools with metadata (see General information on metadata),

T is the period of time (number of days) that metadata will be stored. By default, T = 30 days.

If you have less than 15 GB of free disk space, the metadata

...

 database is overwritten - the new data

...

is written over the oldest data

...

.

The system logs

When calculating the disk subsustem capacity, it is necessary to include at least 1 GB for the system logs archive.

Self-diagnostics service

When calculating disk subsystem capacity,

...

note that self-

...

diagnostics service may generate up to 100 Mbytes of data per day.

The depth of the service

...

internal database

...

is limited to 7 days

...

and

...

512

...

MB.